0=1x^2-6x+9

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Solution for 0=1x^2-6x+9 equation: 



0=1x^2-6x+9

We move all terms to the left:

0-(1x^2-6x+9)=0

We add all the numbers together, and all the variables

-(1x^2-6x+9)=0

We get rid of parentheses

-1x^2+6x-9=0

a = -1; b = 6; c = -9;
Δ = b2-4ac
Δ = 62-4·(-1)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-6}{-2}=+3$

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